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【題目】判定下列函數的奇偶性.

1fx;

2fx

3fx;

4fx=|x+1|+|x-1|.

【答案】1非奇非偶函數,2既是奇函數又是偶函數,

3奇函數,4偶函數

【解析】1fx的定義域是-∞,11,+∞,不關于原點對稱,∴fx是非奇非偶函數.

2fx的定義域是{-1,1},關于原點對稱,且f-1=f1=0,∴f-1=f1,且

f-1=-f1,

函數fx既是奇函數又是偶函數.

3fx的定義域為-∞,+∞,關于原點對稱,

,fx是奇函數.

4fx的定義域為R,

又f-x=|-x+1|+|-x-1|=|x-1|+|x+1|=fx

fx是偶函數.

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