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(文)將圓x2+y2=1按向量a=(1,-1)平移后,恰好與直線x-y+b=0相切,則實數b的值為

A.2±            B.-2±             C.3±            D.-3±

答案: (文)D  圓x2+y2=1,按a=(2,-1)平移后為(x-2)2+(y+1)2=1與x-y+b=0相切,

=1,∴b=-3±,選D.

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