解析：設圓錐母線長為R，底面圓的半徑為r，則r＝Rsin.又底面周長l＝2πr＝Rα，即2πRsin＝Rα，∴α＝2πsin.

∵＜θ＜，∴＜sin＜，∴π＜α＜π.

答案：D

設函數f(x)(x∈R)滿足f(－x)＝f(x)，f(x)＝f(2－x)，且當x∈[0,1]時，f(x)＝x³.又函數g(x)＝|xcos(πx)|，則函數h(x)＝g(x)－f(x)在上的零點個數為                                                                    (　　)

A．5                               B．6

C．7                               D．8